Instructions - Describe the code!
This instruction set will continue to grow once the main round is posted, keep checking back.
Note that these are just examples
, we encourage you to use your own grammar or descriptions!
1
Declarations
string v[200];
v = array of strings of length 200
let v = string array of length 200
let v be of array of length 200 of strings
int n, m;
n, m = integers
create integers n and m
map<string, int> mp;
let mp be a map from string to int
create a map mp from strings to ints
mp = map from string to int
int n, a, maxi = 0;
let n, a, maxi be integers with maxi = 0
n, a, maxi = integers with maxi = 0
2
Input & output
cin >> n >> m;
Read n and m
cout << (sx + tx) / 2 + 1 << " " << (sy + ty) / 2 + 1;
print (sx + tx) / 2 + 1 and (sy + ty) / 2 + 1
print (sx + tx) / 2 + 1, " ", (sy + ty) / 2 + 1
cout << sum << endl
print sum and a new line
print sum
3
Function
int main()
in the main function
in function main
maxi = max(maxi, m[a]);
set maxi to max of maxi and m[a]
maxi = max(maxi, m[a])
4
Loops
for (int i = 0; i < n; ++i)
for i = 0 to n exclusive
for i = 0 to n (exclusive)
for (int i = 0; i < a.size(); i++)
for i = 0 to length of a exclusive
5
Conditionals
if (!first && v[i][j] == 'B') {
if not first and v[i][j] is B
if first is false and v[i][j] is the character B
if (v[i][j] == 'B') {
if v[i][j] is B
if v[i][j] is character B
if v[i][j] is equal to B, do the following.
} else if (i + 1 == n)
else if i + 1 = n do the following
else if i + 1 is equal to n
int n, m;
n, m = integers
create integers n and m
6
Assignments
sx = i;
set sx to i
sx = i
assign i to sx
a = abs(b[i] - c[j])
set x to absolute value of b[i] - c[j]
7
Other operations
sum++
increment sum
add 1 to sum
increase sum by 1
x = a && b
set x to a and b
set x to a && b
x = a and b
